10q^2+10=29q

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Solution for 10q^2+10=29q equation:


Simplifying
10q2 + 10 = 29q

Reorder the terms:
10 + 10q2 = 29q

Solving
10 + 10q2 = 29q

Solving for variable 'q'.

Reorder the terms:
10 + -29q + 10q2 = 29q + -29q

Combine like terms: 29q + -29q = 0
10 + -29q + 10q2 = 0

Factor a trinomial.
(2 + -5q)(5 + -2q) = 0

Subproblem 1

Set the factor '(2 + -5q)' equal to zero and attempt to solve: Simplifying 2 + -5q = 0 Solving 2 + -5q = 0 Move all terms containing q to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5q = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5q = 0 + -2 -5q = 0 + -2 Combine like terms: 0 + -2 = -2 -5q = -2 Divide each side by '-5'. q = 0.4 Simplifying q = 0.4

Subproblem 2

Set the factor '(5 + -2q)' equal to zero and attempt to solve: Simplifying 5 + -2q = 0 Solving 5 + -2q = 0 Move all terms containing q to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2q = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2q = 0 + -5 -2q = 0 + -5 Combine like terms: 0 + -5 = -5 -2q = -5 Divide each side by '-2'. q = 2.5 Simplifying q = 2.5

Solution

q = {0.4, 2.5}

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